Solution: Cs50 Tideman

3 3 1 2 3 1 3 2 2 1 3 This input represents an election with 3 voters and 3 candidates. The output of the program should be:

// Function to eliminate candidate void eliminate_candidate(candidate_t *candidates_list, int candidates, int eliminated) { // Decrement vote counts for eliminated candidate for (int i = 0; i < candidates; i++) { if (candidates_list[i].id == eliminated) { candidates_list[i].votes = 0; } } } Cs50 Tideman Solution

// Allocate memory for voters and candidates *voters_prefs = malloc(*voters * sizeof(voter_t)); candidate_t *candidates_list = malloc(*candidates * sizeof(candidate_t)); 3 3 1 2 3 1 3 2

// Function to recount votes void recount_votes(voter_t *voters_prefs, int voters, candidate_t *candidates_list, int candidates) { // Recount votes for (int i = 0; i < voters; i++) { for (int j = 0; j < candidates; j++) { if (candidates_list[voters_prefs[i].preferences[j] - 1].votes == 0) { // Move to next preference voters_prefs[i].preferences[j] = -1; } else { break; } } } } } else { break

winner = check_for_winner(candidates_list, candidates); }

// Function to count first-place votes void count_first_place_votes(voter_t *voters_prefs, int voters, candidate_t *candidates_list, int candidates) { // Initialize vote counts to 0 for (int i = 0; i < candidates; i++) { candidates_list[i].votes = 0; }

candidate_t *candidates_list = malloc(candidates * sizeof(candidate_t)); for (int i = 0; i < candidates; i++) { candidates_list[i].id = i + 1; }